1) For the process H2O(l) (1 bar, 373 K) → H2O(S) (1 bar,373 K), the correct set of thermodynamic parameters isΔ A) $\triangle G = 0, \triangle S = +ve$ B) $\triangle G = 0, \triangle S = -ve$ C) $\triangle G = +ve, \triangle S = 0$ D) $\triangle G = -ve, \triangle S = +ve$ Answer: Option AExplanation:Since liquid is passing into the gaseous phase so entropy will increase and at 373 K during the phase transformation it remains at equilibrium. So, ΔG = 0.
