1)

A barmagnet of magneticmoment M, is placed in a magnetic field of induction B. The torque exerted on it is 


A) $\vec{M}.\vec{B}$

B) $-\vec{M}.\vec{B}$

C) $\vec{M}\times\vec{B}$

D) $-\vec{B}.\vec{M}$

Answer:

Option C

Explanation:

$\tau=MB \sin\theta=\vec{M}\times\vec{B}$