Answer:
Option A
Explanation:
Charge resides on the outer surface of a conducting hollow sphere of radius R. We consider a spherical surface of radius r < R. By Gauss theorem
$\int_{s}^{} \vec{E}.\vec{d}s = \frac{1}{\epsilon_{0}}$× Charge enclosed or
$E\times4\pi r^{2} =\frac{1}{\epsilon_{0}}\times0$
i.e electric field inside a hollow sphere is zero.