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An alternating voltage of 220 V 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedence of the circuit is

$\frac{\pi}{5000}$

$\frac{1000}{\pi}$

$500\pi$

$\frac{5000}{\pi}$

Option D

Impedance of a capacitor is $X_{c} = \frac{1}{\omega c}$

$X_{c} = \frac{1}{2\pi fc}$

= $\frac{1}{2\pi\times50\times2\times10^{-6}} = \frac{5000}{\pi}$

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