Discussion Forum



1)

The current in a coil of L = 40 mH is to be increased uniformly from 1 A to 11 A in 4 milli sec. The induced e.m.f will be


A) 100 V

B) 0.4 V

C) 440 V

D) 40 V

Answer:

Option A

Explanation:

e=LdIdt=40×10−3(11−1)4×10−3=100V