Physics | VITEEE 2017 | Discussion Page

A vessel of depth 2d cm is half-filled with a liquid of refractive index μ₁, and the upper half with a liquid of refractive index μ₂. The apparent depth of the vessel seen perpendicularly is

$\left(\frac{\mu_{1}\mu_{2}}{\mu_{1}+\mu_{2}}\right)d$

$\frac{d}{\mu_{1}}+\frac{d}{\mu_{2}}$

$\left(\frac{1}{\mu_{1}}+\frac{1}{\mu_{2}}\right)2d$

$\left(\frac{1}{\mu_{1}\mu_{2}}\right)2d$

Answer:

Option B

Explanation:

Apparent Depth = $\frac{d}{\mu_{1}}+\frac{d}{\mu_{2}}$

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Answer:

Explanation: