Physics | VITEEE 2017 | Discussion Page

Processing math: 100%

Two bodies A and B having masses in the ratio of 3 : 1 possess the same kinetic energy. The ratio of linear momentum of B to A is

A) 1:3

B) 3:1

C) 1:

$\sqrt{3}$

$\sqrt{3}$ :1

Option C

As $\frac{1}{2}m_Av_A^2 = \frac{1}{2}m_{B}v_B^2$

$\frac{v_{A}}{v_{B}} = \sqrt{\frac{m_{B}}{m_{A}}}$

$\frac{P_{B}}{P_{A}} = \frac{m_{B}v_{B}}{m_{A}v_{A}}$

$\frac{m_{B}}{m_{A}}\sqrt{\frac{m_{A}}{m_{B}}} =\sqrt{\frac{m_{B}}{m_{A}}}$ = $\frac{1}{\sqrt{3}}$

Discussion Forum