Discussion Forum



1)

If the kinetic energy of a moving particle is E, then the de-Broglie wavelength is


A) $\lambda =h\sqrt{2mE}$

B) $\lambda =\sqrt{\frac{2mE}{h}}$

C) $\lambda =\frac{h}{\sqrt{2mE}}$

D) $\lambda =\frac{hE}{\sqrt{2mE}}$

Answer:

Option C

Explanation:

E = $\frac{1}{2}mv^{2}$ or $mv = \sqrt{2mE}$

So $\lambda = \frac{h}{mv}$ = $\frac{h}{\sqrt{2mE}}$