1)

The condition that the line xp+yq = 1 be a normal to the parabola y= 4ax is


A) p3=2ap2+aq2

B) p3=2aq2+ap2

C) q3=2ap2+aq2

D) None of these

Answer:

Option A

Explanation:

The line  xp+yq = 1 be a normal to the parabola y= 4ax if, for some value of m, it is identical with

y = mx-2am - am3 i.e.  mx-y = (2am+ am3)

Comparing coefficients, we get 

m1/p=11/q=2am+am31 → mp = -q

.'. m= -q/p and mp = m(2a+am2)

or p = 2a+aq2p2 or p3=2ap2+aq2