Answer:
Option A
Explanation:
The line xp+yq = 1 be a normal to the parabola y2 = 4ax if, for some value of m, it is identical with
y = mx-2am - am3 i.e. mx-y = (2am+ am3)
Comparing coefficients, we get
m1/p=−11/q=2am+am31 → mp = -q
.'. m= -q/p and mp = m(2a+am2)
or p = 2a+aq2p2 or p3=2ap2+aq2