Discussion Forum

A and B are events such that P(A υ B) = 3/4, $P(A\cap B) =1/4, P(\bar{A}) = 2/3then, P(\bar{A}\cap B)$ is

Answer:

Explanation:

$P(A\cup B) = P(A) + P(B) - P(A\cap B)$

3/4  $=1- P(\bar{A}) + P(B) - 1/4$

1 = 1-2/3 + P(B) → P(B) = 2/3

Now ,$P(\bar{A}\cap B)$ = P(B) - $P(A\cap B)$ = 2/3 - 1/4 = 5/12