1) If $Z= \frac{7-i}{3-4i}$ , then z14 = A) $2^{7}$ B) $2^{7}i$ C) $2^{14}i$ D) $-2^{7}i$ Answer: Option DExplanation:$Z= \frac{7-i}{3-4i}\times\frac{3+4i}{3+4i}$ $\frac{21+25i+4}{16+9}=\frac{25(1+i)}{25}=(1+i)$ $z^{14} = (1+i)^{14} = \left[\left(1+i\right)^{2}\right]^{7}=(2i)^{7}$ = $2^{7}i^{7} = -2^{7}i$
