Discussion Forum

A substance C₄H₁₀O yields on oxidation a compound, C₄H₈O which gives an oxime and a positive iodoform test. The original substance on treatment with conc. H₂SO₄ gives C₄H₈. The structure of the compound is

Answer:

Explanation:

Thus $C_{4}H_{8}O$ should be $CH_{3}COCH_{2}CH_{3}$, hence C₄H₁₀O should be $CH_{3}CHOHCH_{2}CH_{3}$