1) Standard entropies of X2 , Y2 and XY3 are 60, 30 and 50 JK-1 mol-1 respectively. For the reaction $\frac{1}{2}X_{2}+ \frac{3}{2}Y_{2}\rightleftharpoons XY_{3} \triangle H = - 30KJ$ to be at equilibrium, the temperature should be A) 750K B) 1000K C) 1250K D) 500 K Answer: Option AExplanation:ΔS for the reaction, $\frac{1}{2}X_{2}+ \frac{3}{2}Y_{2}\rightleftharpoons XY_{3}$ ΔS = 50-(30+60)= -40J For equilibrium ΔG = 0= ΔH - TΔS T = ΔH/ΔS = -30000/-40 = 750K