Discussion Forum

The half-life period of a first-order chemical reaction is 6.93 minutes. The time required for the completion of 99% of the chemical reaction will be (log 2 = 0.301)

Answer:

Explanation:

For first order reaction, 

$k = \frac{0.693}{t_{1/2}} = \frac{0.693}{6.93}$

$k = \frac{2.303}{t}log\frac{100}{100-99}$

$\frac{0.693}{6.93}$ = $\frac{2.303}{t}log\frac{100}{100-99}$

$\frac{0.693}{6.93}$ = $\frac{2.303\times2}{t}$

t = 46.06 minutes