Chemistry | VITEEE 2017 | Discussion Page

For a first order reaction A → P, the temperature (T) dependent rate constant (k) was found to follow the equation

log k = - (2000)1/T + 6.0 . The pre-exponential factor A and the activation energy E_a respectively, are

$1.0\times 10^{6}s^{-1} and 9.2kJ mol^{-1}$

$6.0s^{-1} and 16.6kJ mol^{-1}$

$1.0\times 10^{6}s^{-1} and 16.6kJ mol^{-1}$

$1.0\times 10^{6}s^{-1} and 38.3kJ mol^{-1}$

Option D

$\log_{}{k}=\log_{}{A}-\frac{E_{a}}{2.303RT}$ ....(1)

Also given log k = 6.0 - (2000)1/T .....(2)

On comparing equations, (1) and (2)

log A = 6.0 → A = 10⁶ s^-1

and $\frac{E_{a}}{2.303R}$ = 2000

→ E_a = 2000x2.303 x 8.314 = 38.29kJmol^-1

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