Discussion Forum

1)

A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 s. Then the coefficient of friction is (Take g= 10 ms^-2)

 

Answer:

Option A

Explanation:

$a=\mu g=\frac{6}{10}$     [using v= u+at]

$\Rightarrow\mu =\frac{6}{10\times g}=\frac{6}{10\times10}=0.06$