1) A marble block of mass 2 kg lying on ice when given a velocity of 6 m/s is stopped by friction in 10 s. Then the coefficient of friction is (Take g= 10 ms-2) A) 0.06 B) 0.03 C) 0.04 D) 0.01 Answer: Option AExplanation:$a=\mu g=\frac{6}{10}$ [using v= u+at] $\Rightarrow\mu =\frac{6}{10\times g}=\frac{6}{10\times10}=0.06$
