1) If the nuclear radius of 27 Al is 3.6 Fermi, the approximate nuclear radius of 64Cu in Fermi is A) 4.8 B) 3.6 C) 2.4 D) 1.2 Answer: Option AExplanation: Nuclear radius , $r\propto A^{1/3}$ Where A is mass number $\frac{r_{Cu}}{r_{Al}}=\left(\frac{A_{Cu}}{A_{Al}}\right)^{1/3}=\left(\frac{64}{27}\right)^{1/3}$ $\Rightarrow r_{Cu}=3.6\left(\frac{4}{3}\right)=4.8 Fermi$
