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 The magnetic flux in a closed circuit of resistance 10 Ω varies with time as  $\phi=(2t-4t^{2}+1)$ . the  current in the loop will change its direction after a time of

Answer:

Explanation:

$e=-\frac{d\phi}{dt}=[-2+8t+0]$

 $\Rightarrow 8t=2\Rightarrow t=\frac{1}{4}sec=0.25 sec$