Discussion Forum

Two point dipoles $p\hat{k}$   and $\frac{p}{2}\hat{k}$  are located at (0,0,0) and  (1m,0,2m) respectively . The resultant electric field due to the two dipoles at the point (1m, 0,0) is 

Answer:

Explanation:

 The given point is on axis of  $\frac{\overrightarrow{p}}{2}$ dipole and at equatorial line of  $\overrightarrow{p}$ dipole so that field at given point is ($\overrightarrow{E_{1}}+\overrightarrow{E_{2}}$)

$\overrightarrow{E_{1}}=\frac{2K(p/2)}{2^{3}}=\frac{K_{p}}{8}(+\hat{k})$

$\overrightarrow{E_{2}}=\frac{K_{p}}{1}(-\hat{k})$

$\overrightarrow{E_{1}}+\overrightarrow{E_{2}}=-\frac{7}{8}K_{p}(-\hat{k})=\frac{-7 p}{32\pi\epsilon_{0}}\hat{k}$