Discussion Forum

 The  terminal speed of a sphere of gold (density =19.5 kg/m³) is 0.2 m/s ina viscous  liquid (density =1.5 kg/m³) , find the terminal speed of a sphere of silver (density= 10.5 kg/m³) of the same size in the same liquid 

Answer:

Explanation:

Terminal velocity,

$v_{T}=\frac{2r^{2}(d_{1}-d_{2})g}{9\eta}$

$\frac{v_{T_{2}}}{0.2}=\frac{(10.5-1.5)}{(19.5-1.5)} \Rightarrow v_{T_{2}}=0.2\times\frac{9}{18}$

 $\therefore$  $v_{T_{2}}=  0.1 m/s$