Discussion Forum

In a reaction, A→ Products, when start is made from 80 x 10^-2 M of A, the half-life is found to be 120 minutes. For the initial concentration  4.0 x 10^-2 M  , the half-life of the reaction becomes 240 minutes. The order of the reaction is 

Answer:

Explanation:

$\frac{(t_{1}/2)_{1}}{(t_{1}/2)_{2}}=(\frac{a_{2}}{a_{2}})^{n-1}$

$\frac{120}{240}=(\frac{4\times 10^{-2}}{8\times 10^{-2}})^{n-1}; n=2$