1) In a reaction, A→ Products, when start is made from 80 x 10-2 M of A, the half-life is found to be 120 minutes. For the initial concentration 4.0 x 10-2 M , the half-life of the reaction becomes 240 minutes. The order of the reaction is A) 0 B) 1 C) 2 D) 0.5 Answer: Option CExplanation:$\frac{(t_{1}/2)_{1}}{(t_{1}/2)_{2}}=(\frac{a_{2}}{a_{2}})^{n-1}$ $\frac{120}{240}=(\frac{4\times 10^{-2}}{8\times 10^{-2}})^{n-1}; n=2$
