Answer:
Option B
Explanation:
$RT In K =-\triangle G^{0}=T\triangle S^{0}-\triangle H^{0}$;
$ In K =\frac{\triangle S^{0}}{R}-\frac{\triangle H^{0}}{RT}$
Thus, a plot of In K versus 1/T (abscissa) will be straight line with slope equal to
$\frac{-\triangle H^{0}}{R}$ and intercept $\frac{\triangle S^{0}}{R}$