1)

A moles of PCl5 is heated in a closed container to equilibrium   PCl5PCl3(g)+Cl2(g) at a pressure of p  atm. If x moles of PCl5 disscociate at equilibrium  , then

 


A) xa=KpKp+P

B) xa=(Kp+PKp)1/2

C) xa=(KpP)1/2

D) xa=(KpKp+P)1/2

Answer:

Option D

Explanation:

 PCl5PCl3(g)+Cl2(g) 

 1-α           α             α

 α  = x/a  (degree of dissociation )

 Total moles =  1α+α+α=1+α

Kp=PPCl3×PCl2PPCl5

       =[α1+α.p][α1+α.p]1α1+α.p

 =α2p1α2α=(KpKp+P)1/2