1)

 At 298 K , the conductivity of a saturated solution  , of AgCl  in water is 2.6 x 10-6S cm-1. Its solubility product at 298 K,

 Given :  λ(Ag+)=63.0Scm2mol1

             λ(Cl)=67.0Scm2mol1


A) 2.0×105M2

B) 4.0×1010M2

C) 4.0×1016M2

D) 2.0×108M2

Answer:

Option B

Explanation:

 Solubility 

S=1000kλ0AgCl=1000×2.6×106λ0Ag++λ0Cl

2.6×10363+67=2×105molL1;Ksp=S2