1) At 298 K , the conductivity of a saturated solution , of AgCl in water is 2.6 x 10-6S cm-1. Its solubility product at 298 K, Given : λ∞(Ag+)=63.0Scm2mol−1 λ∞(Cl−)=67.0Scm2mol−1 A) 2.0×10−5M2 B) 4.0×10−10M2 C) 4.0×10−16M2 D) 2.0×10−8M2 Answer: Option BExplanation: Solubility S=1000kλ0AgCl=1000×2.6×10−6λ0Ag++λ0Cl− 2.6×10−363+67=2×10−5molL−1;Ksp=S2