1) For hydrogen -oxygen fuel cell, the cell reaction is $2H_{2}(0)+O_{2}(g)\rightarrow 2H_{2}O(l)$ if $\triangle G_f^0 (H_{2}O)=-237.2kJmol^{-1}$ , then emf of this cell is A) +2.46 V B) -2.46 V C) +1.23 V D) -1.23 V Answer: Option CExplanation: We know $\triangle$ G0= -nFE0 $\therefore$ $E^{0}=\frac{\triangle G^{0}}{nF}$ $= +\frac{237.2\times1000J}{2\times96500}=1.23 V[\therefore n=2]$