1)

An ionic compound has a unit cell consisting of  A ions at the corners of a cube and b ions on the centres of the faces of the cube. The empirical formula for this compound would be


A) $A_{3}B$

B) $AB_{3}$

C) $A_{2}B$

D) AB

Answer:

Option B

Explanation:

 Number of A ions in the unit cell = $\frac{1}{8}\times8=1$

 Number of B ions in the unit cell =  $\frac{1}{2}\times6=3$

 Hence empirical formula of the compound = AB3