1) XeF4 disproportionate in water to give A) Xe+HF B) Xe and $XeO_{3}$ C) $XeOF_{4} $ and HF D) $XeO_{2}Fe $ and HF Answer: Option BExplanation:XeF4 dispropprtionates in water giving solid XeO3 on evaporation $6XeF_{4}+12H_{2}O\rightarrow 2XeO_{3}+24HF+4Xe+3O_{2}$
