Discussion Forum



1)

The correct set of quantum numbers for Rb (atomic number .37 ) is


A) $5,0,0,-\frac{1}{2}$

B) $5,0,0,\frac{1}{2}$

C) $6,0,1,\frac{1}{2}$

D) $5,1,1,\frac{1}{2}$

Answer:

Option A

Explanation:

The electronic configuration for Rb (37) is 

 Rb (37)

  = 1s2  2s2 2p6 3s2 3p6 4s2 3d10  4p6 5s1

 For  5s1, n=5, l=0, m=0 s= $-\frac {1}{2}$