1)

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 The product P for the above given reaction will be


A) m-nitroaniline

B) o-nitroaniline

C) p-nitroaniline

D) both o & p nitroaniline

Answer:

Option D

Explanation:

Nitric acid not only nitrates but also oxidizes the highly reactive ring as well, with loss of much material as dark-coloured tar. Furthermore, in the strongly acidic nitration medium, the amine  is converted into anilinium  ion (-NH3+): substitution is thus controlled not by the -NH2 group but the -NH3 + group  which because of its positive charge  directs the entering  group to the meta-position instead of ortho,  and para

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However, all these difficulties are overcome by protecting the amino group by acetylation, with either acetyl chloride or acetic anhydride. Acetylation (-NH2→ NHCOCH3) coverts -NH2 group to acetamido (-NHCOCH3) group which is 0, p-directing but lesser activating toward electrophilic aromatic substitution than the parent -NH2 group.

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