Answer:
Option D
Explanation:
Let the intensity of unpolarised light be I0. so the intensity of first polaroid is $\frac{I_{0}}{2}$. On rotating through 60° , the intensity of light from second polaroid
$I=\frac{I_{0}}{2}(\cos 60)^{2}=\frac{I_{0}}{2}\frac{I}{4}=\frac{I_{0}}{8}=0.125 I_{0}$
$\therefore$ percentage of incident light transmitted through the system=12.5%