Answer:
Option D
Explanation:
Maximum current flows in the circuit in resonance condition Current in the LCR circuit
$i=\frac{V}{\sqrt{R^{2}+(X_{L}-X_{C})^{2}}}$
For current to be maximum denominator should be minimum
$(X_{L}-X_{C})^{2}$= 0
$\Rightarrow X_{L}=X_{C}\Rightarrow\omega L=\frac{1}{\omega C}$
$\therefore$ $ L=\frac{1}{\omega^{2}C}=\frac{1}{(100)^{2}\times10\times 10^{-6}}$
$ L=\frac{1}{10}H=0.1 H=100 mH$
