Discussion Forum



1)

 A coil of area 5 cm2 having 20 turns is placed in a uniform magnetic field of 103 gausses. The normal the plane of coil makes an angle 30° with the magnetic field. The flux through the coil is 


A) $6.67\times 10^{-4}wb$

B) $3.2\times 10^{-5}wb$

C) $5.9\times 10^{-4}wb$

D) $8.65\times 10^{-4}wb$

Answer:

Option D

Explanation:

Given :N=20

 B= 103 gauss= 103 x 10-4 T= 0.1T

 A= 5 cm2= 5 x 10-4 m2

 $\theta$= 80°

 Flux through the coil =   

$\phi= NBA \cos\theta$

$=20\times 0.1\times 5\times 10^{-4}\times\cos 30^{0}$

 $=10\times 10^{-4}\times \frac{\sqrt{3}}{2}=5\sqrt{3}\times 10^{-4}=865\times 10^{-4}wb$