Discussion Forum



1)

 The angular momentum of an electron in Bohr 's hydrogen atom whose energy is -3.4 e V , is 


A) $\frac{5h}{2\pi}$

B) $\frac{h}{2\pi}$

C) $\frac{h}{\pi}$

D) $\frac{2h}{3\pi}$

Answer:

Option C

Explanation:

Energy of electron on the nth orbit of hydrogen atom

$E_{n}=-\frac{13.6}{n^{2}}eV$

 $\Rightarrow 3.4=-\frac{13.6}{n^{2}}\Rightarrow n^{2}=4$

 or n=2

 Angular momentum  of electron

 $L=\frac{nh}{2\pi}=\frac{2h}{2\pi}=\frac{h}{\pi}$