Physics | VITEEE 2015 | Discussion Page

A nuclear transformation is given by $Y(n,\alpha)\rightarrow _{3}Li^{7}$ .The nucleus of elements Y is

$_{5}Be^{11}$

$_{5}Be^{10}$

$_{5}Be^{9}$

$_{6}Cl^{12}$

Option B

Y(n, $\alpha$ ) the nucleus splits in to $\alpha$ - particle and neutrons

i.e, $_{Z}Y^{A}+_{0}n^{1}\rightarrow_{3}Li^{7}+_{2}He^{4}$

and Z+0=3 +2 or Z=5

So, A+1=7+4

A=10
Hence , the nucleus of element Y is boron

$_{5}Y^{10}=_{5}B^{10}$

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