1) The area of the region bounded by the curves x2+y2=9 and x+y=3 is A) $\frac{9\pi}{4}+\frac{1}{2}$ B) $\frac{9\pi}{4}-\frac{1}{2}$ C) $9\left[\frac{\pi}{4}-\frac{1}{2}\right]$ D) $9\left[\frac{\pi}{4}+\frac{1}{2}\right]$ Answer: Option CExplanation: Area of required region =$\frac{1}{4}$ x Area of circle - Area of $\triangle$ OAB = $\frac{1}{4}\times\pi\times(3)^{2}-\frac{1}{2}\times 3\times3$ = $9\left[\frac{\pi}{4}-\frac{1}{2}\right]$
