Answer:
Option B
Explanation:
[a+b-c}.[(a-b) x(b-c)
=(a+b-c).[a x b-a x c- bx b+ b x c]
= a.(a x b)-a.(a x c)+a.(b x c)+b.
(a x b)-b(a x c)+b. (b x c)- c.(a x b)+ c.( a x c)-c.(b x c)
= a.(b x c)-b .(a x c)-c. (a x b)
=[a b c ] -[b a c]-[c a b]
=[a b c]+[a b c]-[a b c]
=[a b c]= a.(b x c)
