1)

 If p,q, r are  simple propositions with truth values T,F,T , then  the truth value of  $(\sim p\vee q)\wedge  \sim r)$

$\Rightarrow$ p is 


A) true

B) false

C) true , if r is false

D) true, if q is true

Answer:

Option A

Explanation:

$\sim p\vee q$  means $ F\vee F=F,\sim r$ means F

 $\therefore$    $[(\sim P\vee q)\wedge \sim r]\Rightarrow p $ means  T