Answer:
Option D
Explanation:
Given : |z|=$\frac{1}{4}$
Let z'=-1+8z
$\Rightarrow z=\frac{z'+1}{8}\Rightarrow|z|=\frac{|z'+1|}{8}$
$\Rightarrow \frac{1}{4}=\frac{|z'+1|}{8}\Rightarrow |z'+1|=2$
$\therefore$ z' lies ona circle with centre (-1,0) and radius 2.