1) In the cannizzaro reaction given below $2Ph-CHO$ $\underrightarrow{OH^{-}}$ $ Ph-CH_{2}-OH+PhCO_{2}^{-}$ the slowest step is A) the attack of $O^{-}H$ at the carbonyl group B) the transfer of hydride ion to the carbonyl group C) the abstraction of a proton from the carboxylic acid D) the deprotonation of Pb- $CH_{2}OH$ Answer: Option BExplanation:Hydride ion transfer to the carbonyl group is the slowest or the rate-determining steps.
