Discussion Forum



1)

 The dissolution of Al(OH)3 by a solution of NaOH results in the formation of 


A) [Al(H2O)4(OH)2]+

B) [Al(H2O)3(OH)3]

C) [Al(H2O)2(OH)4]−

D) [Al(H2O)6(OH)3]

Answer:

Option C

Explanation:

Al(OH)3  dissolves in NaOH solution to  give  Al(OH)−4  ion which is supposed to have the octahedral complex species 

[Al(OH)4(H2O)2]− in aqueous solution 

Al(OH)3+NaOH(aq)→Al(OH)4(H2O)2−(aq)+Na+(aq)