1)

With excess  of water both P2O5  and PCl5 give


A) $H_{3}PO_{3}$

B) $H_{3}PO_{2}$

C) $H_{3}PO_{4}$

D) $H_{4}P_{2}O_{7}$

Answer:

Option C

Explanation:

Both  P2O5  and PCl5 give  $H_{3}PO_{4}$ with excess of water

$P_{2}O_{5}+3H_{2}O\rightarrow 2H_{3}PO_{4}$

$PCl_{5}+4H_{2}O\rightarrow H_{3}PO_{4}+5HCl$