Discussion Forum

1)

Consider the following changes

$M(s)\rightarrow M(g)$  ......(i)

$M(g)\rightarrow M^{2+}(g)+2e^{-}$   ...(2)

$M(g)\rightarrow M^{+}(g)+e^{-}$    ....(3)

$M^{+}(g)\rightarrow M^{2+}(g)+e^{-}$  .....(4)

$M^{}(g)\rightarrow M^{2+}(g)+2e^{-}$   .......(5)

The second ionisation energy of M  could be determined from the energy values associated  with

Answer:

Option D

Explanation:

The amount  of energy required to take out an electron from the monopositive cation is called second ionisation energy

$M^{}(g)\rightarrow M^{2+}(g)+2e^{-}$  ....(v)

 $M^{}(g)\rightarrow M^{+}(g)+e^{-}$   ....(iii)

 On substracting eq(iii) from eq.(v)  we get,

 $M\rightarrow M^{2+}+e^{-}$