Discussion Forum

1)

Consider the following changes

$M(s)\rightarrow M(g) $  ......(i)

$M(g)\rightarrow M^{2+}(g)+2e^{-} $   ...(2)

$M(g)\rightarrow M^{+}(g)+e^{-} $    ....(3)

$M^{+}(g)\rightarrow M^{2+}(g)+e^{-} $  .....(4)

$M^{}(g)\rightarrow M^{2+}(g)+2e^{-} $   .......(5)

The second ionisation energy of M  could be determined from the energy values associated  with

Answer:

Option D

Explanation:

The amount  of energy required to take out an electron from the monopositive cation is called second ionisation energy

$M^{}(g)\rightarrow M^{2+}(g)+2e^{-} $  ....(v)

 $M^{}(g)\rightarrow M^{+}(g)+e^{-} $   ....(iii)

 On substracting eq(iii) from eq.(v)  we get,

 $M\rightarrow M^{2+}+e^{-} $