1)

Point out incorrect stability order


A) $[Cu(NH_{3})_{4}]^{2+} < [Cu(en)_{2}]^{2+} < [Cu(trien)]^{2+}$

B) $[{Fe(H_{2}O})_{6}]^{3+}< [Fe(NO_{2})_{6}]^{3-}<[Fe(NH_{3})_{6}]^{3+}$

C) $[{Co(H_{2}O})_{6}]^{3+} <[Rh(H_{2}O)_{6}]^{3+}<[Ir(H_{2}O)_{6}]^{3+}$

D) $[{Cr(NH_{3}})_{6}]^{+} <[Cr(NH_{3})_{6}]^{2+}<[Cr(NH_{3})_{6}]^{3+}$

Answer:

Option B

Explanation:

Increasing order of stability

(a)   $[Cu(NH_{3})_{4}]^{2+}< [Cu(en)_{2}]^{2+}<[Cu(trien)]^{2+}$

 Their  formation of entropy increases in the same order. Ligand denticity is increased

(b)  $[{Fe(H_{2}O})_{6}]^{3+}< [Fe(NO_{2})_{6}]^{3-}<[Fe(NH_{3})_{6}]^{3+}$

$\because$  NH3  is weaker ligand than NO2-

 $\therefore$ The correct stability order is 

$[{Fe(H_{2}O})_{}]^{3+} <[Fe(NH_{3})_{6}]^{3+}<[Fe(NO_{2})_{6}]^{3-}$

(c) $[{Co(H_{2}O})_{6}]^{3+} <[Rh(H_{2}O)_{6}]^{3+}<[Ir(H_{2}O)_{6}]^{3+}$ 

 Zeff  value increases from Co3+ to Ir3+

(d)  $[{Cr(NH_{3}})_{6}]^{+} <[Cr(NH_{3})_{6}]^{2+}<[Cr(NH_{3})_{6}]^{3+}$

O.S of Cr atom increases from +1 to +3