1)

Gaseous benzene reacts with hydrogen gas in presence of a nickel catalyst to form gaseous cyclohexane according to the reaction.

 $C_{6}H_{6}(g)+3H_{2}(g)\rightarrow C_{6}H_{12}(g)$

A mixture of C6H6 and excess H2 has a pressure of 60mm of Hg in an unknown volume. After the gas had been passed over a nickel catalyst and all the benzene converted to cyclohexane ,the pressure of the gas was 30mm of Hg in the same volume at the same temperature. The fraction of C6H6 (by volume) present in the original  volume is 


A) 1/3

B) 1/4

C) 1/5

D) 1/6

Answer:

Option D

Explanation:

Let initially ,pressure of C6H6 (g) ids  p1   mm and for H2(g) is p2 mm

 p1+p2= 60 mm ....(i)

 After the reaction pressure of C6H6(g)=0 (as all C6H6  has reacted)

 H2(g)= p2-3p1

 So, total pressure =  $p_{2}-3p_{1}+p_{1}=30$mm

 $p_{2}-2p_{1}=30$mm ..........(ii)

 On solving equation (i) and (ii)

 $p_{1}$=10mm, $p_{2}$=50mm

 Fraction of C6H6 by volume= moles fraction of pressure =  $\frac{10}{60}=\frac{1}{6}$