Chemistry | VITEEE 2015 | Discussion Page

The molarity of NO₃ in the solution after 2L of 3 M AgNO₃ is mixed with 3L of 1M BaCl₂ is

A) 1.2 M

B) 1.5M

C) 0.5 M

D) 0.4 M

Option A

2L of 3M AgNO₃ will contain 6 moles of AgNO₃.

3L of 1M BaCl₂ will contain 3 moles of BaCl₂

$2AgNO_{3}+BaCl_{2}\rightarrow 2AgCl+Ba(NO_{3})_{2}$

So, 6 moles of AgNO₃ will react with 3 moles on BaCl₂ it means , two solution will react completely to form 3 moles of

Ba(NO₃)₂ =6 moles of NO₃^- ions in 2⁺

3=5 L solution

Hence, molarity of $NO_{3}^{-}$=6/5=1.2 M

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