1)

A saturated solution of H2 S in 0.1 \M HCl at 250 C  contains S2- ion concentration of 10-23 mol L-1. The solubility product of some sulphides are CuS= 10-44, FeS =10-14 , MnS=10-15 , CdS=10-25 . If 0.01 M solution of these salts in 1 M  HCl are saturated with H2S which of these will be precipitated?


A) All

B) All except MnS

C) AU except MnS and FeS

D) Only -CuS

Answer:

Option C

Explanation:

$[S^{2-}]=10^{-23} mol L^{-1}$

$[M^{2+}]=10^{-2} M$

 Ionic product  ,  $K_{1p}=[M^{2+}][S^{2-}] =10^{-25}$

  $\therefore$ ionic product is greater than  Ksp of CuS and CdS.

 Therefore , all except MnS and FeS are prescipitated