1) An L-C-R circuit contains $R= 50 \Omega$ , L=1 mH and C=$0.1 \mu F$ . The impedance of the circuit will be minimum for a frequency of A) $\frac{10^{5}}{2 \pi}$Hz B) $\frac{10^{6}}{2 \pi}$Hz C) $2 \pi \times 10^{5}$Hz D) $2 \pi \times 10^{6}$Hz Answer: Option AExplanation:Impedence of L-C-R circuit will be minimum for a resonant frequency so, $v_{0}=\frac{1}{2\pi\sqrt{LC}}$ = $v_{0}=\frac{1}{2\pi\sqrt{1\times10^{-3}\times0.1\times10^{-6}}}=\frac{10^{5}}{2 \pi}Hz$
