1) Two coils have a mutual inductance of 0.55H. The current changes in the first coil according to equation $I=I_{0}\sin \omega t$. where ,$I_{0}=10A$ and $\omega=100\pi$ rad/s The maximum value of emf in the second coil is A) $ 2 \pi$ B) $ 5 \pi$ C) $ \pi$ D) $ 4 \pi$ Answer: Option BExplanation:E.M.F e= $M \frac{di}{dt}=0.005 \times \frac{d}{dt} (i_{0}\sin \omega t)$ =$0.005 \times i_{0} \cos \omega t$ $e _{max}=0.005 \times 10 \times 100 \pi=5 \pi$
