1) If the electron in the hydrogen atom jumps from the third orbit to second orbit , the wavelength of the emitted radiation in term of Rydberg constant A) $\frac{6}{5R}$ B) $\frac{36}{5R}$ C) $\frac{64}{7R}$ D) none of these Answer: Option BExplanation: As we know, $\frac{1}{\lambda}=R\left(\frac{1}{2^{2}}-\frac{1}{3^{2}}\right)=R\left(\frac{1}{4}-\frac{1}{9}\right)$ $\frac{1}{\lambda}=R\left(\frac{9-4}{36}\right)=\frac{5R}{36}$ $\therefore$ $\lambda=\frac{36}{5R}$
