Discussion Forum

In hydrogen discharge tube, it is observed that through a given cross-section $3.31 \times 10^{15}$ electrons are moving from right to left and $3.12 \times 10^{5}$ protons are moving from left to right . The current in the discharge  tube and its direction will be 

Answer:

Explanation:

Here, number of electrons $n_{e}=3.13 \times 10^{15}$

and number of protons $n_{p}=3.12 \times 10^{15}$

 Current $I= n_{e}q_{e} +n_{p}q_{p}$

  $=3.13 \times 10^{15} \times 1.6 \times 10^{-17} +3.12 \times 10^{15}\times 1.6 \times 10^{-19}$

  $=1 \times 10^{-3}=1mA$

Now, due to excess charge on electrons , the direction of the current will be towards right